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Formulae of Algebra II
| 08.11.2012, 8:04:09 PM |
Algebra Word | Excel | ℕ ⊂ ℤ ⊂ ℚ ⊂ ℝ
| natural()=subset(integer())=subset(rational())=subset(real()) | △ABC, a⊥h, p=P÷2:
S=ah/2=0.5ah=√p͞(͞p͞−͞a͞)͞(͞p͞−͞b͞)͞(͞p͞−͞c͞) | triangle(ABC), a=perpend(h), p=P/2:
S=ah/2=0.5ah=sqrt(p(p-a)(p-b)(p-c)) | √x̅=a, a²=x | sqrt(x)=a, a^2=x | √−͞x=ai, x>0 | sqrt(-x)=ai, x>0 | −√x̅=−a, x>0 | -sqrt(x)=-a, x>0 | △ABC, ∠C=90°, AB=c, BC=a, AC=b:
a²+b²=c² | triangle(ABC), angle(C)=90*degree(), AB=c, BC=a, AC=b: a^2+b^2=c^2
| √x͞y=√x̅×√y̅
| sqrt(xy)=sqrt(x)*sqrt(y) | √x͞/͞y=√x̅/√y̅
| sqrt(x/y)=sqrt(x)/sqrt(y) | √x͞²=|x|
| sqrt(x^2)=|x| | CLASSIC QUADRATIC EQUATION: ax²+bx+c=0
D=b²−4ac
x=(−b±√D̅)/2a
THEOREM OF VIETA: x₁+x₂=−b/a, x₁x₂=c/a
| CLASSIC QUADRATIC EQUATION: ax^2+bx+c=0
D=b^2-4ac
x=(-b(+-)sqrt(D))/2a
THEOREM OF VIETA: x(1)+x(2)=-b/a, x(1)x(2)=c/a
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REDUCED QUADRATIC EQUATION: x²+px+q=0
D=p²−4q
x=(−p±√D̅)÷2
THEOREM OF VIETA: x₁+x₂=−p, x₁x₂=q |
REDUCED QUADRATIC EQUATION: x^2+px+q=0
D=p^2-4q
x=(-p(+-)sqrt(D))/2
THEOREM OF VIETA: x(1)+x(2)=-p, x(1)x(2)=q | √a͞±͞√͞b̅=√(a͞+͞√͞(͞a͞²͞−͞b͞)͞/͞2±√a͞−͞√͞(͞a͞²͞−͞b͞)͞/͞2 | sqrt(a(+-)sqrt(b))=sqrt((a+sqrt(a^2-b))/2)(+-)sqrt((a-sqrt(a^2-b))/2) | Pₙ=n! | P(n)=n! | △ABC WITH BISECTOR AD:
BD/CD=AB/AC
| triangle(ABC) WITH BISECTOR AD: BD/CD=AB/AC
| △ABC∼△A₁B₁C₁:
∠A=∠A₁, ∠B=∠B₁, ∠C=∠C₁
AB/A₁B₁=BC/B₁C₁=AC/A₁C₁=k S/S₁=k²
| triangle(ABC)=similar(triangle(A(1)B(1)C(1))): angle(A)=angle(A(1)), angle(B)=angle(B(1)), angle(C)=angle(C(1))
AB/A(1)B(1)=BC/B(1)C(1)=AC/A(1)C(1)=k
S/S(1)=k^2
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Category: My files | Added by: Elektronika_XQ-19
| Tags: algebra, math
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